Sec 2 statistics: centre and grouped data

A mean uses every value and its frequency. A median needs ordered observations. Grouped intervals hide exact values, so a midpoint-based mean is an estimate.

What this guide covers

Selected Sec 2 S1 measures of centre and grouped-mean skills. Quartiles, box plots and standard deviation are later work.

Count observations, not rows

For a frequency table, total all value×frequency products and divide by the sum of frequencies. For a median, use the middle position(s) in the ordered data. For grouped intervals, use midpoints and say the result is estimated.

Read a frequency table

Values 2, 4 and 6 have frequencies 3, 5 and 2. Find the mean, median and mode.

  1. There are 3+5+2=10 observations, with total 2(3)+4(5)+6(2)=38. Mean =3810=3.8.
  2. In the ordered list, positions 5 and 6 are both 4, so median =4.
  3. The most frequent value is 4 (five occurrences), so mode =4.

Check: The mean 3.8 lies between the smallest and largest observed values, 2 and 6.

Try it yourself

Work on paper, then compare the steps. These checks do not establish mastery.

Find the mean and median of 3, 7, 9 and 11.

Mean =(3+7+9+11)4=304=7.5. The ordered middle pair is 7 and 9, so median =(7+9)2=8.

Ten values are grouped: 0≤x<10 has frequency 4; 10≤x<20 has frequency 6. Estimate the mean and explain why it is not exact.

Use midpoints 5 and 15: estimated mean =[4(5)+6(15)]10=11010=11. Exact positions inside each interval are unknown, so this is an estimate.

Where this connects

Sources and scope

Original Mentora data sets aligned to selected Sec 2 S1 content in the MOE G2/G3 Mathematics syllabus. No school table was copied.

MOE G2 and G3 Mathematics syllabuses ↗