E-Math resources

Circle properties

Circle geometry connects angles and lengths through stated facts: equal radii, a tangent at a named point, or points on the circumference. Name the relevant chord or arc before applying an angle theorem.

What this guide covers

Chord and tangent properties, angles subtended by the same arc, semicircles and cyclic quadrilaterals. Conditions matter more than how a sketch looks. The graph also contains an alternate-segment objective, which is not included here because it is not explicitly listed in this syllabus scope.

Syllabus reference: 2026 Mathematics 4052, G3, page 9. These are Mentora search groupings, not new official syllabus categories.

The content in this guide was also checked against 2027 G3 Mathematics K310, G3, page 9 on 2026-09-12. This is subject-content alignment, not a claim of complete syllabus coverage.

Worked example

O is the centre. A, B and C lie on the circle, with C on the major arc AB. The minor central angle AOB is 124°. Find angle ACB.

Both angles stand on the minor arc AB. The angle at the centre is twice the angle at the circumference, so angle ACB = 124° ÷ 2 = 62°. The position of C ensures that the intended arc is the same.

ABCO124°minor arc AB
O is the centre. A and B bound the highlighted minor arc; C is on the major arc. OA and OB are radii. ∠AOB = 124° and ∠ACB stands on the same minor arc AB.

Try three practice checks

Attempt each on paper before revealing the worked answer. These sample particular skills; they do not diagnose the whole topic or establish mastery.

Check 1

AB is a diameter and C is a different point on the circle. Find angle ACB.

ABCO
AB passes through centre O, so it is a diameter. C is on the circumference. The angle at C stands on the semicircle AB that does not contain C.
Show worked answer

An angle subtended by a diameter at the circumference is a right angle, so angle ACB = 90°.

Check 2

A, B, C, D are in order on a circle. Angle ABC is 107°. Find angle ADC.

ABCD107°
A, B, C and D lie in that order on the circumference. The highlighted arc AC does not contain B. ∠ABC = 107°; ∠ADC is the opposite angle, subtending the other arc AC.
Show worked answer

Opposite angles of a cyclic quadrilateral sum to 180°, so angle ADC = 180° − 107° = 73°.

Check 3

PT is tangent at T to a circle with centre O. OP = 13 cm and OT = 5 cm. Find PT.

OTP5 cm13 cm
PT is tangent at T. OT = 5 cm is perpendicular to PT, and OP = 13 cm. The highlighted right-angle marker at T justifies using Pythagoras.
Show worked answer

A radius is perpendicular to the tangent at the point of contact, so triangle OTP is right-angled at T. PT² = 13² − 5² = 144, giving PT = 12 cm.

Mistakes to watch for

  • Do not halve just any central angle: identify the shared arc and check which side of the chord the point lies on.
  • A tangent is perpendicular to the radius only at its point of contact.
  • Opposite angles sum to 180° only when the quadrilateral is cyclic; a sketch alone does not establish this.

If one of these occurs, compare the relevant step with the worked example, then try a different question before drawing conclusions.

Useful foundations to check

These connections suggest what may help with this skill. Selecting a topic says nothing about your current attainment.

Applications and next topics

Combine circle properties with triangle angle sums, Pythagoras and trigonometry in multi-step geometry. Arc length and sector area are a related mensuration application, not a replacement for angle reasons.

Choose a useful next resource

To understand a recurring error rather than relearn the whole skill: Check why an angle argument loses marks.

Explore the foundations connected to circle properties

Sources and review

Original Mentora public practice, authored for this guide. Worked answers and syllabus mapping checked during editorial QA on 2026-09-12; no independent expert review is claimed. Graph connections are Mentora learning hints, not an official SEAB sequence. Read the source and examination-year notes.